College Algebra (6th Edition)

$-5$
Solve for $x$ $\frac{13x-6}{4}=5x+2$ $13x-6=4(5x+2)$ $13x-6=20x+8$ $13x-20x=8+6$ $-7x=14$ $x=-2$ Solve for $y$ $5-y=7(y+4)+1$ $5-y=7y+28+1$ $5-y=7y+29$ $5-29=7y+y$ $-24=8y$ $y=-3$ Substitute $x$ and $y$ values in $x^{2}-(xy-y) = (-2)^{2}-((-2 \times -3)-(-3))$ $=4-(6+3)$ $=4-9$ $x^{2}-(xy-y) = -5$