Answer
$6$
Work Step by Step
First solve for the second equation
$2(x - 6) = 3x + 2(2x - 1)$
$2x - 12 = 3x + 4x - 2$
$2x - 12 = 7x - 2$
$-5x = 10$
$x = -2$
Plug $x=-2$ into the first equation
$x^{2}- x$
$(-2)^{2}- (-2)$
$4+2 = 6$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 1 - Equations and Inequalities - Exercise Set 1.2 - Page 119: 86
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