## College Algebra (6th Edition)

$6$
First solve for the second equation $2(x - 6) = 3x + 2(2x - 1)$ $2x - 12 = 3x + 4x - 2$ $2x - 12 = 7x - 2$ $-5x = 10$ $x = -2$ Plug $x=-2$ into the first equation $x^{2}- x$ $(-2)^{2}- (-2)$ $4+2 = 6$