Answer
$-7$
Work Step by Step
Solving for $x$
$\frac{3(x+3)}{5}= 2x+6$
Multiplying both sides by $5$
$5(\frac{3(x+3)}{5})=5( 2x+6)$
$3x+9= 10x+30$
$3x-10x=30-9$
$-7x= 21$
$x=-3$
Solving for $y$
$-2y-10= 5y+18$
$-2y- 5y=10+18$
$-7y=28$
$y=-4$
Substituting $x$ and $y$ values in
$x^{2}-(xy-y) = (-3)^{2}-((-3 \times -4)-(-4))$
$= 9-(12+4)$
$= 9-16$
$=-7$
