Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 68



Work Step by Step

$2(x+1)(x-3)^2-3(x+1)^2(x-3)$ (Take out common factor (x+1)(x-3) ) =$(x+1)(x-3)(2(x-3)-3(x+1))$ =$(x+1)(x-3)(2x-6-3x-3)$ =$(x+1)(x-3)(-x-9)$ =$-(x+1)(x-3)(x+9)$
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