Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 45

Answer

$(2x-1)(x^{2}-3)$

Work Step by Step

Expression : $2x^{3}-x^{2}-6x+3 = (2x^{3}-x^{2})-(6x-3)$ (group the terms) = $x^{2}(2x-1)-3(2x-1) = (2x-1)(x^{2}-3)$ (factor out the common factor)
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