Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 25

Answer

$(x-2)(x^{2}+2x+4)$

Work Step by Step

Factor : $x^{3}-8 = x^{3} - 2^{3} $ By the well known formula : $x^{3} - y^{3} = (x-y)(x^{2}+xy+y^{2})$ Hence, $x^{3}-8 = x^{3} - 2^{3} = (x-2)(x^{2}+2x+4)$
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