Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 71

Answer

$(4x+\frac{1}{3})(4x-\frac{1}{3})$

Work Step by Step

$16x^2-\frac{1}{9}=(4x)^2-(\frac{1}{3})^2=(4x+\frac{1}{3})(4x-\frac{1}{3})$
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