Answer
$(x-2)(x+1)(-x+8)=-(x-2)(x+1)(x-8)$
Work Step by Step
$2(x-2)(x+1)^2-3(x-2)^2(x+1)=2(x-2)(x+1)(x+1)-3(x-2)(x-2)(x+1)=(x-2)(x+1)[2(x+1)-3(x-2)]=(x-2)(x+1)(2x+2-3x+6)=(x-2)(x+1)(-x+8)=-(x-2)(x+1)(x-8)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 67
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
