Answer
$(9u^2+1)(3u+1)(3u-1)$
Work Step by Step
$81u^4-1=(9u^2)^2-1^2=(9u^2+1)(9u^2-1)=(9u^2+1)[(3u)^2-1^2]=(9u^2+1)(3u+1)(3u-1)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 17
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