Answer
$(x-\frac{3}{4})(x^2+\frac{3}{4}x+\frac{9}{16})$
Work Step by Step
$x^3-\frac{27}{64}=x^3-(\frac{3}{4})^3=(x-\frac{3}{4})[x^2+x(\frac{3}{4})+(\frac{3}{4})^2]=(x-\frac{3}{4})(x^2+\frac{3}{4}x+\frac{9}{16})$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 76
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