Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 20



Work Step by Step

Expression : $4t^{2}+4t+1 = (2t)^{2}+2(2t)(1)+1$ By the well known formula : $(x+y)^{2} = x^{2} + 2xy + y^{2}$ Put x=2t, y =1 $4t^{2}+4t+1 = (2t)^{2}+2(2t)(1)+1 = (2t+1)^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.