Answer
$(2t+1)^{2}$
Work Step by Step
Expression : $4t^{2}+4t+1 = (2t)^{2}+2(2t)(1)+1$
By the well known formula : $(x+y)^{2} = x^{2} + 2xy + y^{2}$
Put x=2t, y =1
$4t^{2}+4t+1 = (2t)^{2}+2(2t)(1)+1 = (2t+1)^{2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 20
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