## Algebra and Trigonometry 10th Edition

$(3x+2)(9x^{2}-6x+4)$
Expression : $27x^{3}+8 = (3x)^{3}+2^{3}$ By the well known formula : $x^{3}+y^{3}=(x+y)(x^{2}-xy+y^{2})$ Hence, $27x^{3}+8=(3x)^{3}+2^{3}=(3x+2)((3x)^{2}-3x(2)+2^{2})=(3x+2)(9x^{2}-6x+4)$