## Algebra and Trigonometry 10th Edition

$a=21.6$ $b=19.32$ $c=6.36$
Let's find the angle opposite to b: $B=180°-102.4°-16.7°=60.9°$ $\frac{b}{sin~60.9°}=\frac{21.6}{sin~102.4°}$ $b=21.6\frac{sin~60.9°}{sin~102.4°}=19.32$ $\frac{c}{sin~16.7°}=\frac{21.6}{sin~102.4°}$ $c=21.6\frac{sin~16.7°}{sin~102.4°}=6.36$