# Chapter 8 - 8.1 - Law of Sines - 8.1 Exercise - Page 566: 17

B = $21.55^{o}$ C = $122.45^{o}$ c = 11.49

#### Work Step by Step

Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$ To solve the triangle, we need to find C, c, and B. Finding B: We can use the Law of Sines. $\frac{8}{sin(36^{o})} = \frac{5}{sin(B^{o})}$ Therefore, B = $21.55^{o}$ Finding C: Since we know 2 other angles, we can use the fact that a triangle has angles that add to $180^{o}$. 180 - 36 - 21.55 = 122.45 Therefore, C = $122.45^{o}$ Finding c: We can use the Law of Sines. $\frac{8}{sin(36^{o})} = \frac{c}{sin(122.45^{o})}$ Therefore, c = 11.49 In total: B = $21.55^{o}$ C = $122.45^{o}$ c = 11.49

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.