## Algebra and Trigonometry 10th Edition

C = $4.52^{o}$ B = $75.48^{o}$ b = 122.87
Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$ To solve the triangle, we need to find C, B, and b. Finding C: We can use the Law of Sines. $\frac{125}{sin(100^{o})} = \frac{10}{sin(C^{o})}$ Therefore, C = $4.52^{o}$ Finding B: Since we found 2 other angles, we can use the fact that a triangle has angles that add to $180^{o}$. 180 - 4.52 - 100 = 75.48 Therefore, B = $75.48^{o}$ Finding b: We can use the Law of Sines. $\frac{125}{sin(100^{o})} = \frac{b}{sin(75.48^{o})}$ Therefore, b = 122.87 In total: C = $4.52^{o}$ B = $75.48^{o}$ b = 122.87