Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.1 - Law of Sines - 8.1 Exercise - Page 566: 12


$A=5°40'$, $B=8°15'$, $C=166°05$ $a=3.30$, $b=4.8$, $c=8.05$

Work Step by Step

$A=5°40'$, $B=8°15'$ $A+B+C=180°$ $C=180°-5°40'-8°15'=166°05'$ $\frac{a}{sin~5°40'}=\frac{4.8}{sin~8°15'}$ $a=4.8~\frac{sin~5°40'}{sin~8°15'}=3.30$ $\frac{c}{sin~166°05'}=\frac{4.8}{sin~8°15'}$ $c=4.8~\frac{sin~166°05'}{sin~8°15'}=8.05$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.