Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.1 - Law of Sines - 8.1 Exercise - Page 566: 26

Answer

B = $36.82^{o}$ C = $67.18^{o}$ c = 32.30

Work Step by Step

Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$ To solve the triangle, we need to find C, B, and c. Finding B: We can use the Law of Sines. $\frac{34}{sin(76^{o})} = \frac{21}{sin(B^{o})}$ Therefore, B = $36.82^{o}$ Finding C: Since we found 2 other angles, we can use the fact that a triangle has angles that add to $180^{o}$. 180 - 76 - 36.82 = 67.18 Therefore, C = $67.18^{o}$ Finding c: We can use the Law of Sines. $\frac{34}{sin(76^{o})} = \frac{c}{sin(67.18^{o})}$ Therefore, c = 32.30 In total: B = $36.82^{o}$ C = $67.18^{o}$ c = 32.30
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