## Algebra and Trigonometry 10th Edition

A = $48^{o}$ b = 2.29 c = 4.73
Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$ To solve the triangle, we need to find b, c, and A. Finding A: Since we are given 2 other angles, we can use the fact that a triangle has angles that add to $180^{o}$. 180 - 28 - 104 = 48 Therefore, A = $48^{o}$ Finding b: We can use the Law of Sines. $\frac{b}{sin(28^{o})} = \frac{3.625}{sin(48^{o})}$ Therefore, b = 2.29 Finding c: We can use the Law of Sines. $\frac{c}{sin(104^{o})} = \frac{3.625}{sin(48^{o})}$ Therefore, c = 4.73 In total: A = $48^{o}$ b = 2.29 c = 4.73