Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.1 - Law of Sines - 8.1 Exercise - Page 566: 16

Answer

A = $48^{o}$ b = 2.29 c = 4.73

Work Step by Step

Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$ To solve the triangle, we need to find b, c, and A. Finding A: Since we are given 2 other angles, we can use the fact that a triangle has angles that add to $180^{o}$. 180 - 28 - 104 = 48 Therefore, A = $48^{o}$ Finding b: We can use the Law of Sines. $\frac{b}{sin(28^{o})} = \frac{3.625}{sin(48^{o})}$ Therefore, b = 2.29 Finding c: We can use the Law of Sines. $\frac{c}{sin(104^{o})} = \frac{3.625}{sin(48^{o})}$ Therefore, c = 4.73 In total: A = $48^{o}$ b = 2.29 c = 4.73
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