## Algebra and Trigonometry 10th Edition

$a=36.50$ $b=11.05$ $c=45$
Let's find the angle opposite to a: $A=180°-135°-10°=35°$ $\frac{a}{sin~35°}=\frac{45}{sin~135°}$ $a=45\frac{sin~35°}{sin~135°}=36.50$ $\frac{b}{sin~10°}=\frac{45}{sin~135°}$ $b=45\frac{sin~10°}{sin~135°}=11.05$