## Algebra and Trigonometry 10th Edition

B = $101.1^{o}$ a = 1.35 b = 3.23
Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$ To solve the triangle, we need to find a, B, and b. Finding B: Since we are given 2 other angles, we can use the fact that a triangle has angles that add to $180^{o}$. 180 - 24.3 - 54.6 = 101.1 Therefore, B = $101.1^{o}$ Finding a: We can use the Law of Sines. $\frac{a}{sin(24.3^{o})} = \frac{2.68}{sin(54.6^{o})}$ Therefore, a = 1.35 Finding b: We can use the Law of Sines. $\frac{b}{sin(101.1^{o})} = \frac{2.68}{sin(54.6^{o})}$ Therefore, b = 3.23 In total: B = $101.1^{o}$ a = 1.35 b = 3.23