Algebra and Trigonometry 10th Edition

B = $56.24^{o}$ C = $3.76^{o}$ c = 1.89
Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$ To solve the triangle, we need to find C, B, and c. Finding B: We can use the Law of Sines. $\frac{25}{sin(120^{o})} = \frac{24}{sin(B^{o})}$ Therefore, B = $56.24^{o}$ Finding C: Since we found 2 other angles, we can use the fact that a triangle has angles that add to $180^{o}$. 180 - 120 - 56.24 = 3.76 Therefore, C = $3.76^{o}$ Finding c: We can use the Law of Sines. $\frac{25}{sin(120^{o})} = \frac{c}{sin(3.76^{o})}$ Therefore, c = 1.89 In total: B = $56.24^{o}$ C = $3.76^{o}$ c = 1.89