## Algebra: A Combined Approach (4th Edition)

$\dfrac{4x^{2}-4x+1}{2x^{2}+9x-5}=\dfrac{2x-1}{x+5}$
$\dfrac{4x^{2}-4x+1}{2x^{2}+9x-5}$ Factor the perfect square trinomial in the numerator: $\dfrac{4x^{2}-4x+1}{2x^{2}+9x-5}=\dfrac{(2x-1)(2x-1)}{2x^{2}+9x-5}=...$ Factor the denominator and then, simplify: $...=\dfrac{(2x-1)^{2}}{(x+5)(2x-1)}=\dfrac{2x-1}{x+5}$