Answer
$\dfrac{4x^{2}-4x+1}{2x^{2}+9x-5}=\dfrac{2x-1}{x+5}$
Work Step by Step
$\dfrac{4x^{2}-4x+1}{2x^{2}+9x-5}$
Factor the perfect square trinomial in the numerator:
$\dfrac{4x^{2}-4x+1}{2x^{2}+9x-5}=\dfrac{(2x-1)(2x-1)}{2x^{2}+9x-5}=...$
Factor the denominator and then, simplify:
$...=\dfrac{(2x-1)^{2}}{(x+5)(2x-1)}=\dfrac{2x-1}{x+5}$
