Algebra: A Combined Approach (4th Edition)

$\dfrac{7x+35}{x^{2}+5x}=\dfrac{7}{x}$
$\dfrac{7x+35}{x^{2}+5x}$ Take out common factor $7$ in the numerator and common factor $x$ in the denominator. Then simplify: $\dfrac{7x+35}{x^{2}+5x}=\dfrac{7(x+5)}{x(x+5)}=\dfrac{7}{x}$