## Algebra: A Combined Approach (4th Edition)

$\dfrac{x^{2}-16}{x^{2}-8x+16}=\dfrac{x+4}{x-4}$
$\dfrac{x^{2}-16}{x^{2}-8x+16}$ Factor the numerator: $\dfrac{x^{2}-16}{x^{2}-8x+16}=\dfrac{(x-4)(x+4)}{x^{2}-8x+16}=...$ Factor the perfect square trinomial in the denominator. Then, simplify: $...=\dfrac{(x-4)(x+4)}{(x-4)^{2}}=\dfrac{x+4}{x-4}$