Answer
$\dfrac{2}{8x+16}=\dfrac{1}{4x+8}$
Work Step by Step
$\dfrac{2}{8x+16}$
Take out common factor $2$ in the denominator. Then, simplify:
$\dfrac{2}{8x+16}=\dfrac{2}{2(4x+8)}=\dfrac{1}{4x+8}$
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