#### Answer

$\dfrac{2}{8x+16}=\dfrac{1}{4x+8}$

#### Work Step by Step

$\dfrac{2}{8x+16}$
Take out common factor $2$ in the denominator. Then, simplify:
$\dfrac{2}{8x+16}=\dfrac{2}{2(4x+8)}=\dfrac{1}{4x+8}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$\dfrac{2}{8x+16}=\dfrac{1}{4x+8}$

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