Answer
$\dfrac{x-2}{x^{2}-4}=\dfrac{1}{x+2}$
Work Step by Step
$\dfrac{x-2}{x^{2}-4}$
Factor the denominator and simplify:
$\dfrac{x-2}{x^{2}-4}=\dfrac{x-2}{(x-2)(x+2)}=\dfrac{1}{x+2}$
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