## Algebra: A Combined Approach (4th Edition)

$\dfrac{2x^{2}+7x-4}{x^2+3x-4}=\dfrac{2x-1}{x-1}$
$\dfrac{2x^{2}+7x-4}{x^2+3x-4}$ Factor the numerator: $\dfrac{2x^{2}+7x-4}{x^2+3x-4}=\dfrac{(x+4)(2x-1)}{x^{2}+3x-4}=...$ Factor the denominator and then, simplify: $...=\dfrac{(x+4)(2x-1)}{(x+4)(x-1)}=\dfrac{2x-1}{x-1}$