## Algebra: A Combined Approach (4th Edition)

$\dfrac{14x^{2}-21x}{2x-3}=7x$
$\dfrac{14x^{2}-21x}{2x-3}$ Take out common factor $7x$ in the numerator. Then, simplify: $\dfrac{14x^{2}-21x}{2x-3}=\dfrac{7x(2x-3)}{2x-3}=7x$