Answer
$\dfrac{14x^{2}-21x}{2x-3}=7x$
Work Step by Step
$\dfrac{14x^{2}-21x}{2x-3}$
Take out common factor $7x$ in the numerator. Then, simplify:
$\dfrac{14x^{2}-21x}{2x-3}=\dfrac{7x(2x-3)}{2x-3}=7x$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 7 - Section 7.1 - Simplifying Rational Expressions - Exercise Set - Page 490: 43
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