Answer
$\dfrac{x+5}{x^{2}-4x-45}=\dfrac{1}{x-9}$
Work Step by Step
$\dfrac{x+5}{x^{2}-4x-45}$
Factor the denominator and then simplify:
$\dfrac{x+5}{x^{2}-4x-45}=\dfrac{x+5}{(x+5)(x-9)}=\dfrac{1}{x-9}$
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