Answer
$\dfrac{9x+99}{x^{2}+11x}=\dfrac{9}{x}$
Work Step by Step
$\dfrac{9x+99}{x^{2}+11x}$
Take out common factor $9$ in the numerator and common factor $x$ in the denominator. Then simplify:
$\dfrac{9x+99}{x^{2}+11x}=\dfrac{9(x+11)}{x(x+11)}=\dfrac{9}{x}$
