Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.1 - Simplifying Rational Expressions - Exercise Set: 50

Answer

$\dfrac{5x^{2}-500}{35x+350}=\dfrac{x-10}{7}$

Work Step by Step

$\dfrac{5x^{2}-500}{35x+350}$ Take out common factor $5$ in the numerator and common factor $35$ in the denominator: $\dfrac{5x^{2}-500}{35x+350}=\dfrac{5(x^{2}-100)}{35(x+10)}=...$ Factor $x^{2}-100$ and simplify: $...=\dfrac{5(x-10)(x+10)}{35(x+10)}=\dfrac{5(x-10)}{35}=\dfrac{x-10}{7}$
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