Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 788: 58

Answer

7.2 hours for small pipe, 5.2 hours for large pipe

Work Step by Step

large pipe: 2 hours less than the small pipe (x-2) small pipe: x hours together: 3 hours $1/(x-2) + 1/x = 1/3$ $1*(x-2)*x*3/(x-2) + 1*(x-2)*x*3/x = 1*(x-2)*x*3/3$ $3x +3(x-2) = x(x-2)$ $3x+3x-6=x^2-2x$ $6x-6=x^2-2x$ $8x-6=x^2$ $x^2-8x+6=0$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-(-8)±\sqrt {(-8)^2-4*1*6})/2*1$ $x=(8±\sqrt {64-24})/2$ $x=(8±\sqrt {40})/2$ $x=(8±6.32)/2$ $x=(8±6.32)/2$ $x=(8+6.32)/2$ $x=14.32/2$ $x=7.16$ $x=(8±6.32)/2$ $x=(8-6.32)/2$ $x=1.68/2$ $x=.84$ (this is less than two hours, so this answer is not valid) $7.16-2$ $5.16$
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