Answer
$t=-5, 1$
Work Step by Step
$(t+3)^2-2(t+3)-8=0$
$t+3=y$
$(t+3)^2-2(t+3)-8=0$
$y^2-2y-8=0$
$(y-4)(y+2)=0$
$((t+3)-4)((t+3)+2)=0$
$(t+3-4)(t+3+2)=0$
$(t-1)(t+5)=0$
$t-1=0$
$t=1$
$t+5=0$
$t=-5$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 788: 43
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