Answer
$-2i, 2i, -\sqrt 5, \sqrt 5$
Work Step by Step
$p^4-p^2-20=0$
$p^2=x$
$p^4-p^2-20=0$
$(p^2)^2-p^2-20=0$
$x^2-x-20=0$
$(x-5)(x+4)=0$
$x-5=0$
$x=5$
$x+4=0$
$x=-4$
$p^2=x$
$p^2=5$
$\sqrt{p^2}=\sqrt 5$
$p=±\sqrt 5$
$p^2=x$
$p^2=-4$
$\sqrt{p^2}=\sqrt{-4}$
$p=±\sqrt {4*-1}$
$p=±2i$