Answer
$x=5$
Work Step by Step
$x-\sqrt {19-2x}-2=0$
$x-\sqrt {19-2x}-2+\sqrt {19-2x}=0+\sqrt {19-2x}$
$x-2=\sqrt {19-2x}$
$(x-2)^2=(\sqrt {19-2x})^2$
$(x*x+x(-2)+x(-2)+(-2)(-2))=19-2x$
$x^2-4x+4=19-2x$
$x^2-2x-15=0$
$(x-5)(x+3)=0$
$x-5=0$
$x=5$
$x+3=0$
$x=-3$
$x-\sqrt {19-2x}-2=0$
$-3-\sqrt {19-2(-3)}-2=0$
$-3-\sqrt{19+6}-2=0$
$-3-5-2=0$
$-8-2=0$
$-10=0$ (false)