Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 788: 44

Answer

$n=3, 7/2$

Work Step by Step

$(2n-3)^2-7(2n-3)+12=0$ $2n-3=x$ $(2n-3)^2-7(2n-3)+12=0$ $x^2-7x+12=0$ $(x-4)(x-3)=0$ $(2n-3-4)(2n-3-3)=0$ $(2n-7)(2n-6)=0$ $2n-7=0$ $2n=7$ $2n/2=7/2$ $n=7/2$ $2n-6=0$ $2n=6$ $2n/2=6/2$ $n=3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.