Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 788: 56

Answer

jogging: 6 mph bike riding: 10 mph

Work Step by Step

jogging for 3 mi (x mph) bike riding for 5 mi (x+4 mph) $3/x + 5/(x+4) = 1$ $3*x*(x+4)/x + 5*x*(x+4)/(x+4) = 1*x*(x+4)$ $3(x+4) + 5x=x(x+4)$ $3x+12+5x=x^2+4x$ $8x+12=x^2+4x$ $x^2-4x-12=0$ $(x+2)(x-6)=0$ $x+2=0$ $x=-2$ (not a valid answer since we can't have a negative time) $x-6=0$ $x=6$ $x+4$ $6+4$ $10$
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