Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 75



Work Step by Step

$=(a^{-1}b^{3}c/a^{2}b^{4})^{6}$ $=(b^{3}c/a^{1}a^{2}b^{4})^{6}$ (since $a^{-1}=1/a$) $=(c/a^{(2+1)}b^{(4-3)})^{6}$ (since $a^{3}*a^{2}=a^{(3+2)}$) $=(c/a^{(2+1)}b^{(4-3)})^{6}$ $=(c/a^{3}b)^{6}$ $=c^{6}/a^{(3*6)}b^{6}$ (since $(a^{b})^{c}=a^{bc}$) $=c^{6}/a^{18}b^{6}$
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