## Algebra 1: Common Core (15th Edition)

$\frac{3}{2n}$
You have $\frac{3n^2(5^0)}{2n^3}$.Simplify the expression: $\frac{3n^2}{2n^3}$ -any number raised to 0 always equals 1 so $5^{0}$=1- $\frac{3n^2}{2n^3}$ -subtract the exponents in order to simplify them- $n^{2-3}$=$n^{-1}$=$\frac{1}{n}$ The simplified expression is $\frac{3}{2n}$.