Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 62



Work Step by Step

You have $\frac{3x^3}{(3x)^3}$. Simplify the expression: $\frac{3x^3}{3^3x^3}$ -apply rule (ab)${^n}$=$a^{n} $$b^{n}$- $\frac{1}{3^2}$ -cancel out the common factor which is 3- =$\frac{1}{9}$
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