Answer
$\frac{x^6}{9y^8}$
Work Step by Step
You are given ($\frac{3xy^5}{x^4y}$$)^{-2}$.Simplify the expression:
($\frac{x^4y}{3xy^5}$$)^{2}$ -Use the exponent rule that $x^{-y}$=$\frac{1}{x^y}$-
($\frac{x^4{^-}{^1}y^1{^-}{^5}}{3}$$)^{2}$ -subtract the exponents since you are dividing powers with the same base-
($\frac{x^3y{^-}{^4}}{3}$$)^{2}$ -simplify the expression-
($\frac{x^3}{3y^4}$$)^{2}$ -Use the exponent rule that $x^{-y}$=$\frac{1}{x^y}$-
$\frac{x^6}{9y^8}$ -raise the numerator and denominator to the power 2-
The simplified expression is $\frac{x^6}{9y^8}$
