## Algebra 1: Common Core (15th Edition)

$\frac{y^1{^0}}{2x^5}$
You have $\frac{4x^-{^2}y^4}{8x^3y^-{^6}}$. Simplify the expression: $\frac{x^-{^2}y^4}{2x^3y^-{^6}}$. -cancel out the common factor which is 4- $\frac{y^1{^0}}{2x^5}$. -subtract exponents with the same base- The simplified expression is $\frac{y^1{^0}}{2x^5}$