Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 69

Answer

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Work Step by Step

We are given $(\frac{3}{x^2})^{-3}$ Method 1: $(\frac{3}{x^2})^{-3}$ $=(\frac{x^2}{3})^3$ $=\frac{x^6}{27}$ Method 2: $(\frac{3}{x^2})^{-3}$ $=\frac{3^{-3}}{(x^2)^{-3}}$ $=\frac{x^6}{27}$ Method 3: $(\frac{3}{x^2})^{-3}$ $=(\frac{x^2}{3})^3$ $=\frac{x^2}{3}.\frac{x^2}{3}.\frac{x^2}{3}$ $=\frac{x^6}{27}$
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