## Algebra 1: Common Core (15th Edition)

We are given $(\frac{3}{x^2})^{-3}$ Method 1: $(\frac{3}{x^2})^{-3}$ $=(\frac{x^2}{3})^3$ $=\frac{x^6}{27}$ Method 2: $(\frac{3}{x^2})^{-3}$ $=\frac{3^{-3}}{(x^2)^{-3}}$ $=\frac{x^6}{27}$ Method 3: $(\frac{3}{x^2})^{-3}$ $=(\frac{x^2}{3})^3$ $=\frac{x^2}{3}.\frac{x^2}{3}.\frac{x^2}{3}$ $=\frac{x^6}{27}$