Answer
See answers below
Work Step by Step
We are given $(\frac{3}{x^2})^{-3}$
Method 1:
$(\frac{3}{x^2})^{-3}$
$=(\frac{x^2}{3})^3$
$=\frac{x^6}{27}$
Method 2:
$(\frac{3}{x^2})^{-3}$
$=\frac{3^{-3}}{(x^2)^{-3}}$
$=\frac{x^6}{27}$
Method 3:
$(\frac{3}{x^2})^{-3}$
$=(\frac{x^2}{3})^3$
$=\frac{x^2}{3}.\frac{x^2}{3}.\frac{x^2}{3}$
$=\frac{x^6}{27}$