Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 77



Work Step by Step

$=((4x)^{2}y/xy^{4})^{-2}$ $=(16x^{2}y/xy^{4})^{-2}$ $=(16x/y^{3})^{-2}$ (since $a^{3}*a^{2}=a^{(3+2)}$) $=(y^{3}/16x)^{2}$ (since $a^{-1}=1/a$) $=(y^{(3*2)}/(16x)^{2})$ (since $(a/b)^{c}=(a^{c}/b^{c})$) $=(y^{6}/256x^{2})$
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