Answer
$\frac{2b^5}{3a}$
Work Step by Step
We are given:
$\frac{(6a^3)(8b^4)}{(2a^4)(36b^{-1})}$
$=3a^{3-4}\frac{2}{9}b^{4-(-1))}$
$=\frac{2b^5}{3a}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 78
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