Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 78



Work Step by Step

We are given: $\frac{(6a^3)(8b^4)}{(2a^4)(36b^{-1})}$ $=3a^{3-4}\frac{2}{9}b^{4-(-1))}$ $=\frac{2b^5}{3a}$
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