Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 61



Work Step by Step

You have ($\frac{2m^4}{m^2}$$)^{-4}$.Simplify the expression: $\frac{2m^4}{m^2}$=2$m^{2}$ -subtract the exponents because they have the same base- (2$m^{2}$$)^{-4}$ -apply exponent rule $x^{-y}$=$\frac{1}{x^y}$- $\frac{1}{(2m^2)^4}$ -apply rule (ab)${^n}$=$a^{n} $$b^{n}$- 2$^4$=16 and (m$^2$)$^4$=m$^8$ The simplified expression is $\frac{1}{16m^8}.$
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