## Algebra 1: Common Core (15th Edition)

$\frac{1}{a^9}$
You have ($\frac{a^4a}{a^2}$$)^{-3}.Simplify the expression: a^{4+1-2} -simplify the expression insides the parentheses by adding the exponents on the numerator and then subtracting 2 because you are dividing- (a^3)^-$$^3$ apply exponent rule $x^{-y}$=$\frac{1}{x^y}$- $\frac{1}{(a^3)^3}$ -simplify the exponents- The simplified expression is $\frac{1}{a^9}.$