Answer
$\frac{1}{a^9}$
Work Step by Step
You have ($\frac{a^4a}{a^2}$$)^{-3}$.Simplify the expression:
$a^{4+1-2}$ -simplify the expression insides the parentheses by adding the exponents on the numerator and then subtracting 2 because you are dividing-
(a$^3$)$^-$$^3$ apply exponent rule $x^{-y}$=$\frac{1}{x^y}$-
$\frac{1}{(a^3)^3}$ -simplify the exponents-
The simplified expression is $\frac{1}{a^9}.$
