Answer
Balanced nuclear equation:
$^{35}_{16}S -- \gt ^{35}_{17}Cl + {_-}^{0}_{1}e$
Work Step by Step
1. Identify the reaction.
- In a $\beta$ decay, one neutron from the initial atom breaks into one proton and one electron. The proton remains in the nucleus, and the electron is released. We represent that electron by: $({_-}_{1}^0e)$.
2. Determine the atomic number and symbol for : $sulfur$, and write its complete symbol.
- It is 16, and "S". Therefore, the symbol for sulfur-35 is: $^{35}_{16}S$.
3. Now, add 1 to the atomic number of that sulfur:
$^{35}_{16}S --\gt ^{35}_{17}?$
4. Identify the symbol for the element with atomic number equal to 17.
- It is "Cl". So, the main product of that reaction will be: $^{35}_{17}Cl$
5. Write the complete equation:
$^{35}_{16}S -- \gt ^{35}_{17}Cl + {_-}^{0}_{1}e$
