Answer
$^{18}_{9}F -- \gt ^{18}_{8}O + {_+}_{1}^0e$
Work Step by Step
1. Identify the reaction.
- In a $\beta ^+$ emission, one proton from the initial atom breaks into a neutron and a positron. The neutron remains in the nucleus, and the positron is released. We represent that positron by: $({_+}_{1}^0e)$.
2. Determine the atomic number for : $F$, and write its complete symbol.
- It is 9. Therefore, the symbol for F-18 is: $^{18}_{9}F$.
3. Now, subtract 1 from the atomic number of that fluorine:
$^{18}_{9}F --\gt ^{18}_{8}?$
4. Identify the symbol for the element with atomic number equal to 8.
- It is "O". So, the main product of that reaction will be: $^{18}_{8}O$
5. Write the complete equation:
$^{18}_{9}F -- \gt ^{18}_{8}O + {_+}_{1}^0e$
