Answer
Complete nuclear equation:
$^{126}_{50}Sn -- \gt ^{126}_{51}Sb + ^{0}_{-1}e$
Work Step by Step
1. Identify the reaction.
- In a $\beta$ decay, one neutron from the initial atom breaks into one proton and one electron. The proton remains in the nucleus, and the electron is released. We represent that electron by: $(_{-1}^0e)$.
2. Determine the atomic number and symbol for : $tin$, and write its complete symbol.
- It is 50 and "Sn". Therefore, the symbol for tin-126 is: $^{126}_{50}Sn$.
3. Now, add 1 to the atomic number of that tin:
$^{126}_{50}Sn --\gt ^{126}_{51}?$
4. Identify the symbol for the element with atomic number equal to 51.
- It is "Sb". So, the main product of that reaction will be: $^{126}_{51}Sb$
5. Write the complete equation:
$^{126}_{50}Sn -- \gt ^{126}_{51}Sb + ^{0}_{-1}e$