Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 5 - Section 5.6 - Nuclear Fission and Fusion - Understanding the Concepts - Page 162: 5.55d

Answer

Complete nuclear equation: $^{126}_{50}Sn -- \gt ^{126}_{51}Sb + ^{0}_{-1}e$

Work Step by Step

1. Identify the reaction. - In a $\beta$ decay, one neutron from the initial atom breaks into one proton and one electron. The proton remains in the nucleus, and the electron is released. We represent that electron by: $(_{-1}^0e)$. 2. Determine the atomic number and symbol for : $tin$, and write its complete symbol. - It is 50 and "Sn". Therefore, the symbol for tin-126 is: $^{126}_{50}Sn$. 3. Now, add 1 to the atomic number of that tin: $^{126}_{50}Sn --\gt ^{126}_{51}?$ 4. Identify the symbol for the element with atomic number equal to 51. - It is "Sb". So, the main product of that reaction will be: $^{126}_{51}Sb$ 5. Write the complete equation: $^{126}_{50}Sn -- \gt ^{126}_{51}Sb + ^{0}_{-1}e$
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